Answer:
Option A
Explanation:
Molality
(m) = Number of moles of solute / mass of solvent (in g) x 1000
= Mass of solute(in g)x 1000/ Molecular weight of solute
x mass of solvent (in g)
$=\frac{W_{solute} \times 1000}{M_{solute}\times W_{solvent}}$
$ =\frac{15.2 \times 1000}{60\times 150}=1.689 mol/kg$